(3-2x)^2-1=-16

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Solution for (3-2x)^2-1=-16 equation:



(3-2x)^2-1=-16
We move all terms to the left:
(3-2x)^2-1-(-16)=0
We add all the numbers together, and all the variables
(-2x+3)^2-1-(-16)=0
We add all the numbers together, and all the variables
(-2x+3)^2+15=0
We move all terms containing x to the left, all other terms to the right
(-2x+3)^2=-15

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